3/1/2024 0 Comments Fluid force on vertical side of tank the weight density of water is 62.4 trapazoid![]() Common weight densities: Water 62.4 pounds per cubic footSeawater 64.0 pounds per cubic foot Pascal's principle: The pressure exerted by a fluid at a depth 2istransmitted equally in all directions. Round your answer to two decimal places. Net vertical force weight of water contained in semicircular volume RBP + Weight of oil contained in arc portion OQP of the cylinder. Find: the hydrostatic pressure on the bottom of the tank the hydrostatic force on the bottom, and the hydrostatic force on one end of the tank. (The weight-density of water is 62.4 pounds per cubic foot. 2 from your text: A tank is 8 m long, 4 m wide, 2 m high and contains kerosene with density 820 kg/m3 to a depth of 1.5 m. Say that the trough is full to within 1 foot of the top with water of weight density 62.4 pounds/ft 3, and a pump is used to empty the tank until the water remaining in the tank is 1 foot deep. For example, suppose that in a setting similar to the problem posed in Preview Activity 6.62. Pressure T A2 where Ais the weight-density of the liquid per unit of volume. 100 (1 rating) Transcribed image text: Find the fluid force on the vertical side of the tank, where the dimensions are given in feet. Consider a trough with triangular ends, as pictured in Figure 6.17, where the tank is 10 feet long, the top is 5 feet wide, and the tank is 4 feet deep. ![]() What is the meaning of the value you find? Why?īecause work is calculated by the rule \( W = F \cdot d\), whenever the force \( F\) is constant, it follows that we can use a definite integral to compute the work accomplished by a varying force. Evaluate the definite integral \( \int^50_0 B(h) dh\).= B(h)\Delta h\) measure for a given value of \( h\) and a small positive value of \( \Delta h\)? height 3 meters depth of the fluid and is deduce from the diagram. ![]()
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